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Definite Integration question

2020 · 8 Jan · Shift 2 · Q28

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PYQ Library
JEE Main
Mathematics
Definite Integration
2020 · 8 Jan · Shift 2 · Q28

Definite Integration question

2020 · 8 Jan · Shift 2 · Q28

JEE MainMathematicsDefinite IntegrationMCQ+4 / −1

If

I = \int\limits_1^2 {{{dx} \over {\sqrt {2{x^3} - 9{x^2} + 12x + 4} }}}

, then :

A
${1 \over 16} \lt {I^2} \lt {1 \over 9}$
B
${1 \over 8} \lt {I^2} \lt {1 \over 4}$
C
${1 \over 9} \lt {I^2} \lt {1 \over 8}$
D
${1 \over 6} \lt {I^2} \lt {1 \over 2}$

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