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Complex Numbers question

2020 · 3 Sep · Shift 1 · Q37
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Complex Numbers question

2020 · 3 Sep · Shift 1 · Q37

JEE MainMathematicsComplex NumbersNumerical+4 / −1
If (1+i1−i)m2=(1+i1−i)n3=1{\left( {{{1 + i} \over {1 - i}}} \right)^{{m \over 2}}} = {\left( {{{1 + i} \over {1 - i}}} \right)^{{n \over 3}}} = 1(1−i1+i​)2m​=(1−i1+i​)3n​=1, (m, n ∈\in∈ N) then the greatest common divisor of the least values of m and n is ‾\underline{\hspace{2cm}}​ .
Numerical answer
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