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Complex Numbers question

2019 · 8 Apr · Shift 1 · Q37
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  5. /2019 · 8 Apr · Shift 1 · Q37

Complex Numbers question

2019 · 8 Apr · Shift 1 · Q37

JEE MainMathematicsComplex NumbersMCQ+4 / −1
If α\alphaα and β\betaβ be the roots of the equation x2 – 2x + 2 = 0, then the least value of n for which (αβ)n=1{\left( {{\alpha \over \beta }} \right)^n} = 1(βα​)n=1 is :
  1. A
    2
  2. B
    5
  3. C
    4
  4. D
    3
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