Doubts
Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents
Sign in to save progress →
Doubts
Sign in

Complex Numbers question

2019 · 10 Apr · Shift 1 · Q27
Guest · try one question or challengeGuest · try one question or challenge
  1. PYQ Library
  2. /JEE Main
  3. /Mathematics
  4. /Complex Numbers
  5. /2019 · 10 Apr · Shift 1 · Q27

Complex Numbers question

2019 · 10 Apr · Shift 1 · Q27

JEE MainMathematicsComplex NumbersMCQ+4 / −1
If a > 0 and z = (1+i)2a−i{{{{\left( {1 + i} \right)}^2}} \over {a - i}}a−i(1+i)2​, has magnitude 25\sqrt {{2 \over 5}}52​​, then z‾\overline zz is equal to :
  1. A
    −15+35i- {1 \over 5} + {3 \over 5}i−51​+53​i
  2. B
    −15−35i- {1 \over 5} - {3 \over 5}i−51​−53​i
  3. C
    15−35i{1 \over 5} - {3 \over 5}i51​−53​i
  4. D
    −35−15i- {3 \over 5} - {1 \over 5}i−53​−51​i
PreviousNext

More from Complex Numbers

  • If z and w are two complex numbers such that |zw| = 1 and arg(z) – arg(w) = 2π​ , then :2019 · MCQ
  • Let z1 and z2 be any two non-zero complex numbers such that 3∣z1​∣=4∣z2​∣. If z=2z2​3z1​​+3z1​2z2​​ then :2019 · MCQ
  • Let z=(23​​+2i​)5+(23​​−2i​)5. If R(z) and 1(z) respectively denote the real and imaginary parts of z, then :2019 · MCQ
  • Let (−2−31​i)3=27x+iy​(i=−1​), where x and y are real numbers, then y − x equals :2019 · MCQ
  • Let z be a complex number such that |z| + z = 3 + i (where i = −1​). Then |z| is equal to :2019 · MCQ
  • The equation |z – i| = |z – 1|, i = −1​, represents :2019 · MCQ
  • Let z ∈ C with Im(z) = 10 and it satisfies 2z+n2z−n​ = 2i - 1 for some natural number n. Then :2019 · MCQ
  • If z+αz−α​(α∈R) is a purely imaginary number and | z | = 2, then a value of α is :2019 · MCQ