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Binomial Theorem question

2024 · 5 Apr · Shift 2 · Q36
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  5. /2024 · 5 Apr · Shift 2 · Q36

Binomial Theorem question

2024 · 5 Apr · Shift 2 · Q36

JEE MainMathematicsBinomial TheoremMCQ+4 / −1
If the constant term in the expansion of (35x+2x53)12,xeq0\left(\frac{\sqrt[5]{3}}{x}+\frac{2 x}{\sqrt[3]{5}}\right)^{12}, x eq 0(x53​​+35​2x​)12,xeq0, is α×28×35\alpha \times 2^8 \times \sqrt[5]{3}α×28×53​, then 25α25 \alpha25α is equal to :
  1. A
    724
  2. B
    742
  3. C
    693
  4. D
    639
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