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Binomial Theorem question

2023 · 31 Jan · Shift 1 · Q42
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  5. /2023 · 31 Jan · Shift 1 · Q42

Binomial Theorem question

2023 · 31 Jan · Shift 1 · Q42

JEE MainMathematicsBinomial TheoremNumerical+4 / −1
Let α>0\alpha\gt 0α>0, be the smallest number such that the expansion of (x23+2x3)30\left(x^{\frac{2}{3}}+\frac{2}{x^{3}}\right)^{30}(x32​+x32​)30 has a term βx−α,β∈N\beta x^{-\alpha}, \beta \in \mathbb{N}βx−α,β∈N. Then α\alphaα is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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