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Binomial Theorem question

2022 · 25 Jul · Shift 1 · Q38
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  5. /2022 · 25 Jul · Shift 1 · Q38

Binomial Theorem question

2022 · 25 Jul · Shift 1 · Q38

JEE MainMathematicsBinomial TheoremNumerical+4 / −1
If the maximum value of the term independent of ttt in the expansion of (t2x15+(1−x)110t)15,x⩾0\left(\mathrm{t}^{2} x^{\frac{1}{5}}+\frac{(1-x)^{\frac{1}{10}}}{\mathrm{t}}\right)^{15}, x \geqslant 0(t2x51​+t(1−x)101​​)15,x⩾0, is K\mathrm{K}K, then 8 K8 \mathrm{~K}8 K is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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