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Binomial Theorem question

2022 · 28 Jun · Shift 2 · Q25
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  5. /2022 · 28 Jun · Shift 2 · Q25

Binomial Theorem question

2022 · 28 Jun · Shift 2 · Q25

JEE MainMathematicsBinomial TheoremMCQ+4 / −1
The term independent of x in the expansion of (1−x2+3x3)(52x3−15x2)11, xe0(1 - {x^2} + 3{x^3}){\left( {{5 \over 2}{x^3} - {1 \over {5{x^2}}}} \right)^{11}},\,x e 0(1−x2+3x3)(25​x3−5x21​)11,xe0 is :
  1. A
    740{7 \over {40}}407​
  2. B
    33200{33 \over {200}}20033​
  3. C
    39200{39 \over {200}}20039​
  4. D
    1150{11 \over {50}}5011​
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