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Binomial Theorem question

2022 · 30 Jun · Shift 1 · Q27
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  5. /2022 · 30 Jun · Shift 1 · Q27

Binomial Theorem question

2022 · 30 Jun · Shift 1 · Q27

JEE MainMathematicsBinomial TheoremMCQ+4 / −1
For two positive real numbers a and b such that 1a2+1b3=4{1 \over {{a^2}}} + {1 \over {{b^3}}} = 4a21​+b31​=4, then minimum value of the constant term in the expansion of (ax18+bx−112)10{\left( {a{x^{{1 \over 8}}} + b{x^{ - {1 \over {12}}}}} \right)^{10}}(ax81​+bx−121​)10 is :
  1. A
    1052{{105} \over 2}2105​
  2. B
    1054{{105} \over 4}4105​
  3. C
    1058{{105} \over 8}8105​
  4. D
    10516{{105} \over 16}16105​
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