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Binomial Theorem question

2022 · 28 Jun · Shift 1 · Q41
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  5. /2022 · 28 Jun · Shift 1 · Q41

Binomial Theorem question

2022 · 28 Jun · Shift 1 · Q41

JEE MainMathematicsBinomial TheoremNumerical+4 / −1
The number of positive integers k such that the constant term in the binomial expansion of (2x3+3xk)12{\left( {2{x^3} + {3 \over {{x^k}}}} \right)^{12}}(2x3+xk3​)12, x eee 0 is 28 . l, where l is an odd integer, is ‾\underline{\hspace{2cm}}​.
Numerical answer
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