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Binomial Theorem question

2020 · 2 Sep · Shift 1 · Q24
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  2. /JEE Main
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  5. /2020 · 2 Sep · Shift 1 · Q24

Binomial Theorem question

2020 · 2 Sep · Shift 1 · Q24

JEE MainMathematicsBinomial TheoremMCQ+4 / −1
Let α\alphaα> 0, β\betaβ> 0 be such that α\alphaα 3 + β\betaβ 2 = 4. If the maximum value of the term independent of x in the binomial expansion of (αx19+βx−16)10{\left( {\alpha {x^{{1 \over 9}}} + \beta {x^{ - {1 \over 6}}}} \right)^{10}}(αx91​+βx−61​)10 is 10k, then k is equal to :
  1. A
    176
  2. B
    336
  3. C
    352
  4. D
    84
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