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Binomial Theorem question

2020 · 6 Sep · Shift 1 · Q32
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  5. /2020 · 6 Sep · Shift 1 · Q32

Binomial Theorem question

2020 · 6 Sep · Shift 1 · Q32

JEE MainMathematicsBinomial TheoremMCQ+4 / −1
If {p} denotes the fractional part of the number p, then {32008}\left\{ {{{{3^{200}}} \over 8}} \right\}{83200​}, is equal to :
  1. A
    58{5 \over 8}85​
  2. B
    78{7 \over 8}87​
  3. C
    18{1 \over 8}81​
  4. D
    38{3 \over 8}83​
View written solutionFree

Correct answer: C

  1. We need the fractional part of {32008}.\left\{\frac{3^{200}}{8}\right\}.{83200​}.

  2. The fractional part of a number xxx is {x}=x−⌊x⌋.\{x\}=x-\lfloor x\rfloor.{x}=x−⌊x⌋. So for a rational number with denominator 888, we just need the remainder of the numerator modulo 888.

  3. Compute 3200(mod8)3^{200} \pmod{8}3200(mod8).

    First note: 32=9≡1(mod8).3^2=9 \equiv 1 \pmod{8}.32=9≡1(mod8).

    Therefore, 3200=(32)100≡1100=1(mod8).3^{200}=(3^2)^{100} \equiv 1^{100}=1 \pmod{8}.3200=(32)100≡1100=1(mod8).

  4. So we can write 3200=8k+13^{200}=8k+13200=8k+1 for some integer kkk.

    Hence, 32008=k+18.\frac{3^{200}}{8}=k+\frac{1}{8}.83200​=k+81​.

  5. Therefore, the fractional part is {32008}=18.\left\{\frac{3^{200}}{8}\right\}=\frac{1}{8}.{83200​}=81​.

  6. Comparing with the options:

    • A: 58\frac{5}{8}85​
    • B: 78\frac{7}{8}87​
    • C: 18\frac{1}{8}81​
    • D: 38\frac{3}{8}83​

    The correct option is C.

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