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Area Under the Curves question

2024 · 8 Apr · Shift 1 · Q59

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JEE Main
Mathematics
Area Under the Curves
2024 · 8 Apr · Shift 1 · Q59

Area Under the Curves question

2024 · 8 Apr · Shift 1 · Q59

JEE MainMathematicsArea Under the CurvesNumerical+4 / −1

Let the area of the region enclosed by the curve

y=\min \{\sin x, \cos x\}

and the

x

axis between

x=-\pi

to

x=\pi

be

A

. Then

A^2

is equal to

\underline{\hspace{2cm}}

.

Numerical answer

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