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Area Under the Curves question

2024 · 29 Jan · Shift 1 · Q56
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  5. /2024 · 29 Jan · Shift 1 · Q56

Area Under the Curves question

2024 · 29 Jan · Shift 1 · Q56

JEE MainMathematicsArea Under the CurvesNumerical+4 / −1
If the points of intersection of two distinct conics x2+y2=4bx^2+y^2=4 bx2+y2=4b and x216+y2b2=1\frac{x^2}{16}+\frac{y^2}{b^2}=116x2​+b2y2​=1 lie on the curve y2=3x2y^2=3 x^2y2=3x2, then 333 \sqrt{3}33​ times the area of the rectangle formed by the intersection points is ‾\underline{\hspace{2cm}}​.
Numerical answer
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