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Area Under the Curves question

2024 · 4 Apr · Shift 1 · Q32

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JEE Main
Mathematics
Area Under the Curves
2024 · 4 Apr · Shift 1 · Q32

Area Under the Curves question

2024 · 4 Apr · Shift 1 · Q32

JEE MainMathematicsArea Under the CurvesMCQ+4 / −1

One of the points of intersection of the curves

y=1+3 x-2 x^2

and

y=\frac{1}{x}

is

\left(\frac{1}{2}, 2\right)

. Let the area of the region enclosed by these curves be

\frac{1}{24}(l \sqrt{5}+\mathrm{m})-\mathrm{n} \log _{\mathrm{e}}(1+\sqrt{5})

, where

l, \mathrm{~m}, \mathrm{n} \in \mathbf{N}

. Then

l+\mathrm{m}+\mathrm{n}

is equal to

A
30
B
29
C
31
D
32

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