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3D Geometry question

2025 · 29 Jan · Shift 1 · Q26
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  5. /2025 · 29 Jan · Shift 1 · Q26

3D Geometry question

2025 · 29 Jan · Shift 1 · Q26

JEE MainMathematics3D GeometryMCQ+4 / −1
Let L1:x−11=y−2−1=z−12\mathrm{L}_1: \frac{x-1}{1}=\frac{y-2}{-1}=\frac{z-1}{2}L1​:1x−1​=−1y−2​=2z−1​ and L2:x+1−1=y−22=z1\mathrm{L}_2: \frac{x+1}{-1}=\frac{y-2}{2}=\frac{z}{1}L2​:−1x+1​=2y−2​=1z​ be two lines. Let L3L_3L3​ be a line passing through the point (α,β,γ)(\alpha, \beta, \gamma)(α,β,γ) and be perpendicular to both L1L_1L1​ and L2L_2L2​. If L3L_3L3​ intersects L1\mathrm{L}_1L1​, then ∣5α−11β−8γ∣|5 \alpha-11 \beta-8 \gamma|∣5α−11β−8γ∣ equals :
  1. A
    25
  2. B
    20
  3. C
    16
  4. D
    18
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