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3D Geometry question

2025 · 29 Jan · Shift 2 · Q43
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  5. /2025 · 29 Jan · Shift 2 · Q43

3D Geometry question

2025 · 29 Jan · Shift 2 · Q43

JEE MainMathematics3D GeometryMCQ+4 / −1
Let P be the foot of the perpendicular from the point (1,2,2)(1,2,2)(1,2,2) on the line L:x−11=y+1−1=z−22\mathrm{L}: \frac{x-1}{1}=\frac{y+1}{-1}=\frac{z-2}{2}L:1x−1​=−1y+1​=2z−2​. Let the line r⃗=(−i^+j^−2k^)+λ(i^−j^+k^),λ∈R\vec{r}=(-\hat{i}+\hat{j}-2 \hat{k})+\lambda(\hat{i}-\hat{j}+\hat{k}), \lambda \in \mathbf{R}r=(−i^+j^​−2k^)+λ(i^−j^​+k^),λ∈R, intersect the line L at Q . Then 2(PQ)22(\mathrm{PQ})^22(PQ)2 is equal to :
  1. A
    25
  2. B
    27
  3. C
    19
  4. D
    29
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