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3D Geometry question

2024 · 1 Feb · Shift 1 · Q59
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  5. /2024 · 1 Feb · Shift 1 · Q59

3D Geometry question

2024 · 1 Feb · Shift 1 · Q59

JEE MainMathematics3D GeometryNumerical+4 / −1
Let the line of the shortest distance between the lines L1:r→=(i^+2j^+3k^)+λ(i^−j^+k^) and L2:r→=(4i^+5j^+6k^)+μ(i^+j^−k^)\begin{aligned} & \mathrm{L}_1: \overrightarrow{\mathrm{r}}=(\hat{i}+2 \hat{j}+3 \hat{k})+\lambda(\hat{i}-\hat{j}+\hat{k}) \text { and } \\\\ & \mathrm{L}_2: \overrightarrow{\mathrm{r}}=(4 \hat{i}+5 \hat{j}+6 \hat{k})+\mu(\hat{i}+\hat{j}-\hat{k}) \end{aligned}​L1​:r=(i^+2j^​+3k^)+λ(i^−j^​+k^) and L2​:r=(4i^+5j^​+6k^)+μ(i^+j^​−k^)​ intersect L1\mathrm{L}_1L1​ and L2\mathrm{L}_2L2​ at P\mathrm{P}P and Q\mathrm{Q}Q respectively. If (α,β,γ)(\alpha, \beta, \gamma)(α,β,γ) is the mid point of the line segment PQ\mathrm{PQ}PQ, then 2(α+β+γ)2(\alpha+\beta+\gamma)2(α+β+γ) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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