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3D Geometry question

2024 · 1 Feb · Shift 1 · Q50
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  5. /2024 · 1 Feb · Shift 1 · Q50

3D Geometry question

2024 · 1 Feb · Shift 1 · Q50

JEE MainMathematics3D GeometryMCQ+4 / −1
If the shortest distance between the lines x−λ−2=y−21=z−11\frac{x-\lambda}{-2}=\frac{y-2}{1}=\frac{z-1}{1}−2x−λ​=1y−2​=1z−1​ and x−31=y−1−2=z−21\frac{x-\sqrt{3}}{1}=\frac{y-1}{-2}=\frac{z-2}{1}1x−3​​=−2y−1​=1z−2​ is 1 , then the sum of all possible values of λ\lambdaλ is :
  1. A
    0
  2. B
    232 \sqrt{3}23​
  3. C
    333 \sqrt{3}33​
  4. D
    −23-2 \sqrt{3}−23​
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