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3D Geometry question

2025 · 3 Apr · Shift 2 · Q39
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  5. /2025 · 3 Apr · Shift 2 · Q39

3D Geometry question

2025 · 3 Apr · Shift 2 · Q39

JEE MainMathematics3D GeometryMCQ+4 / −1
The distance of the point (7,10,11)(7,10,11)(7,10,11) from the line x−41=y−40=z−23\frac{x-4}{1}=\frac{y-4}{0}=\frac{z-2}{3}1x−4​=0y−4​=3z−2​ along the line x−92=y−133=z−176\frac{x-9}{2}=\frac{y-13}{3}=\frac{z-17}{6}2x−9​=3y−13​=6z−17​ is
  1. A
    16
  2. B
    12
  3. C
    18
  4. D
    14
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