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3D Geometry question

2024 · 30 Jan · Shift 1 · Q57

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JEE Main
Mathematics
3D Geometry
2024 · 30 Jan · Shift 1 · Q57

3D Geometry question

2024 · 30 Jan · Shift 1 · Q57

JEE MainMathematics3D GeometryNumerical+4 / −1

If

\mathrm{d}_1

is the shortest distance between the lines

x+1=2 y=-12 z, x=y+2=6 z-6

and

\mathrm{d}_2

is the shortest distance between the lines

\frac{x-1}{2}=\frac{y+8}{-7}=\frac{z-4}{5}, \frac{x-1}{2}=\frac{y-2}{1}=\frac{z-6}{-3}

, then the value of

\frac{32 \sqrt{3} \mathrm{~d}_1}{\mathrm{~d}_2}

is :

Numerical answer

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