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3D Geometry question

2020 · 8 Jan · Shift 1 · Q24

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PYQ Library
JEE Main
Mathematics
3D Geometry
2020 · 8 Jan · Shift 1 · Q24

3D Geometry question

2020 · 8 Jan · Shift 1 · Q24

JEE MainMathematics3D GeometryMCQ+4 / −1

The shortest distance between the lines

{{x - 3} \over 3} = {{y - 8} \over { - 1}} = {{z - 3} \over 1}

and

{{x + 3} \over { - 3}} = {{y + 7} \over 2} = {{z - 6} \over 4}

is :

A
3
B
${7 \over 2}\sqrt {30}$
C
$3\sqrt {30}$
D
$2\sqrt {30}$

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