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Thermodynamics question

2025 · 28 Jan · Shift 2 · Q24
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Thermodynamics question

2025 · 28 Jan · Shift 2 · Q24

JEE MainChemistryThermodynamicsNumerical+4 / −1
Consider the following data : Heat of formation of CO2(g)=−393.5 kJ mol−1\mathrm{CO}_2(\mathrm{g})=-393.5 \mathrm{~kJ} \mathrm{~mol}{ }^{-1}CO2​(g)=−393.5 kJ mol−1 Heat of formation of H2O(l)=−286.0 kJ mol−1\mathrm{H}_2 \mathrm{O}(\mathrm{l})=-286.0 \mathrm{~kJ} \mathrm{~mol}{ }^{-1}H2​O(l)=−286.0 kJ mol−1 Heat of combustion of benzene =−3267.0 kJ mol−1=-3267.0 \mathrm{~kJ} \mathrm{~mol}^{-1}=−3267.0 kJ mol−1 The heat of formation of benzene is ‾\underline{\hspace{2cm}}​kJmol−1\mathrm{kJ} \mathrm{mol}^{-1}kJmol−1. (Nearest integer)
Numerical answer
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