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Thermodynamics question

2025 · 3 Apr · Shift 2 · Q24
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Thermodynamics question

2025 · 3 Apr · Shift 2 · Q24

JEE MainChemistryThermodynamicsNumerical+4 / −1
A perfect gas ( 0.1 mol ) having C‾v=1.50R\overline{\mathrm{C}}_v=1.50 \mathrm{R}Cv​=1.50R(independent of temperature) undergoes the above transformation from point 1 to point 4. If each step is reversible, the total work done (w) while going from point 1 to point 4 is (−)(-)(−)‾\underline{\hspace{2cm}}​JJJ(nearest integer) [Given: R=0.082 L atm K−1 mol−1\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}R=0.082 L atm K−1 mol−1 ] JEE Main 2025 (Online) 3rd April Evening Shift Chemistry - Thermodynamics Question 3 English
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