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Thermodynamics question

2025 · 7 Apr · Shift 2 · Q20
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Thermodynamics question

2025 · 7 Apr · Shift 2 · Q20

JEE MainChemistryThermodynamicsMCQ+4 / −1
The correct statement amongst the following is :
  1. A
    The standard state of a pure gas is the pure gas at a pressure of 1 bar and temperature 273 K.
  2. B
    ΔfH500∘\Delta_f H^{\circ}_{500}Δf​H500∘​ is zero for O2(g)O_2(g)O2​(g).
  3. C
    ΔfH298∘\Delta_f H^{\circ}_{298}Δf​H298∘​ is zero for O(g)O(g)O(g).
  4. D
    The term 'standard state' implies that the temperature is 0°C.
View written solutionFree

Correct answer: B

  1. Recall the definition of standard state

    The standard state of a substance means its most stable form at a given temperature and at a pressure of 1 bar.

    Important point: standard state does not fix the temperature to 273 K273\,\text{K}273K or 0∘C0^\circ C0∘C. The temperature must always be specified separately, commonly 298 K298\,\text{K}298K.

  2. Check option A

    Option A says:

    The standard state of a pure gas is the pure gas at a pressure of 1 bar and temperature 273 K.

    This is incorrect because standard state requires pressure =1=1=1 bar, but temperature is not necessarily 273 K273\,\text{K}273K.

    So, A is false.

  3. Check option B

    Option B says:

    ΔfH500∘\Delta_f H^{\circ}_{500}Δf​H500∘​ is zero for O2(g)O_2(g)O2​(g).

    The standard enthalpy of formation of an element in its most stable standard state is taken as zero at that temperature.

    At 500 K500\,\text{K}500K, oxygen in its standard state is still O2(g)O_2(g)O2​(g).

    Therefore, ΔfH500∘[O2(g)]=0\Delta_f H^{\circ}_{500}[O_2(g)] = 0Δf​H500∘​[O2​(g)]=0

    So, B is true.

  4. Check option C

    Option C says:

    ΔfH298∘\Delta_f H^{\circ}_{298}Δf​H298∘​ is zero for O(g)O(g)O(g).

    This is incorrect because the standard state of oxygen at 298 K298\,\text{K}298K is O2(g)O_2(g)O2​(g), not atomic oxygen O(g)O(g)O(g).

    Since O(g)O(g)O(g) is not the standard state, its enthalpy of formation is not zero.

    So, C is false.

  5. Check option D

    Option D says:

    The term 'standard state' implies that the temperature is 0∘C0^\circ C0∘C.

    This is incorrect. Standard state does not imply any fixed temperature like 0∘C0^\circ C0∘C.

    So, D is false.

  6. Conclusion

    Only option B is correct.

    B\boxed{B}B​

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