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Thermodynamics question

2025 · 3 Apr · Shift 1 · Q25
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  5. /2025 · 3 Apr · Shift 1 · Q25

Thermodynamics question

2025 · 3 Apr · Shift 1 · Q25

JEE MainChemistryThermodynamicsNumerical+4 / −1
Given : ΔH⊖sub [C (graphite )]=710 kJ mol−1ΔC−HH⊖=414 kJ mol−1ΔH−HH⊖=436 kJ mol−1ΔC=CH⊖=611 kJ mol−1\begin{aligned} & \left.\Delta \mathrm{H}^{\ominus}{ }_{\text {sub }}[\mathrm{C} \text { (graphite })\right]=710 \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \Delta_{\mathrm{C}-\mathrm{H}} \mathrm{H}^{\ominus}=414 \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \Delta_{\mathrm{H}-\mathrm{H}} \mathrm{H}^{\ominus}=436 \mathrm{~kJ} \mathrm{~mol}^{-1} \\ & \Delta_{\mathrm{C}}=\mathrm{C} \mathrm{H}^{\ominus}=611 \mathrm{~kJ} \mathrm{~mol}^{-1} \end{aligned}​ΔH⊖sub ​[C (graphite )]=710 kJ mol−1ΔC−H​H⊖=414 kJ mol−1ΔH−H​H⊖=436 kJ mol−1ΔC​=CH⊖=611 kJ mol−1​ The ΔHf⊖\Delta \mathrm{H}_{\mathrm{f}} \ominusΔHf​⊖ for CH2=CH2\mathrm{CH}_2=\mathrm{CH}_2CH2​=CH2​ is ‾\underline{\hspace{2cm}}​kJmol−1\mathrm{kJ} \mathrm{mol}^{-1}kJmol−1 (nearest integer value)
Numerical answer
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