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Thermodynamics question

2025 · 7 Apr · Shift 1 · Q3
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  5. /2025 · 7 Apr · Shift 1 · Q3

Thermodynamics question

2025 · 7 Apr · Shift 1 · Q3

JEE MainChemistryThermodynamicsMCQ+4 / −1
Total enthalpy change for freezing of 1 mol of water at 10∘C10^{\circ} \mathrm{C}10∘C to ice at −10∘C-10^{\circ} \mathrm{C}−10∘C is ‾\underline{\hspace{2cm}}​ (Given: Δfus H=x kJ/mol\Delta_{\text {fus }} \mathrm{H}=x \mathrm{~kJ} / \mathrm{mol}Δfus ​H=x kJ/mol Cp[H2O(l)]=y J mol−1 K−1Cp[H2O( s)]=z J mol−1 K−1\begin{aligned} & \mathrm{C}_{\mathrm{p}}\left[\mathrm{H}_2 \mathrm{O}(\mathrm{l})\right]=y \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1} \\ & \mathrm{C}_{\mathrm{p}}\left[\mathrm{H}_2 \mathrm{O}(\mathrm{~s})\right]=z \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1} \end{aligned}​Cp​[H2​O(l)]=y J mol−1 K−1Cp​[H2​O( s)]=z J mol−1 K−1​
  1. A
    −x−10y−10z-x-10 y-10 z−x−10y−10z
  2. B
    x−10y−10zx-10 y-10 zx−10y−10z
  3. C
    −10(100x+y+z)-10(100 x+y+z)−10(100x+y+z)
  4. D
    10(100x+y+z)10(100 \mathrm{x}+y+z)10(100x+y+z)
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