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Structure of Atom question

2025 · 23 Jan · Shift 2 · Q16
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Structure of Atom question

2025 · 23 Jan · Shift 2 · Q16

JEE MainChemistryStructure of AtomMCQ+4 / −1
Given below are two statements : Statement (I) : For a given shell, the total number of allowed orbitals is given by n2n^2n2. Statement (II) : For any subshell, the spatial orientation of the orbitals is given by −l-l−l to +l+l+l values including zero. In the light of the above statements, choose the correct answer from the options given below :
  1. A
    Both Statement I and Statement II are true
  2. B
    Both Statement I and Statement II are false
  3. C
    Statement I is false but Statement II is true
  4. D
    Statement I is true but Statement II is false
View written solutionFree

Correct answer: A

  1. Check Statement (I): Total number of orbitals in a shell

For a shell with principal quantum number nnn, the allowed subshells have values of lll from: l=0 to n−1l=0 \, \text{to} \, n-1l=0ton−1

For each value of lll, the number of orbitals in that subshell is: 2l+12l+12l+1

So, total number of orbitals in the shell is: ∑l=0n−1(2l+1)\sum_{l=0}^{n-1}(2l+1)∑l=0n−1​(2l+1)

This sum equals: 1+3+5+⋯+(2n−1)=n21+3+5+\cdots +(2n-1)=n^21+3+5+⋯+(2n−1)=n2

Hence, Statement (I) is true.


  1. Check Statement (II): Spatial orientation of orbitals in a subshell

For a given subshell with azimuthal quantum number lll, the magnetic quantum number mlm_lml​ determines the spatial orientation of orbitals.

Its possible values are: ml=−l,−(l−1),…,−1,0,1,…,(l−1),lm_l=-l, -(l-1), \dots, -1, 0, 1, \dots, (l-1), lml​=−l,−(l−1),…,−1,0,1,…,(l−1),l

So the values run from −l-l−l to +l+l+l, including zero.

Hence, Statement (II) is also true.


  1. Conclusion

Both Statement (I) and Statement (II) are true.

Therefore, the correct option is: A\boxed{\text{A}}A​


  1. Comparison with stored answer

Stored correct answer: A

My derived answer: A

So, the derived answer agrees with the stored correct answer.

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