According to the wave-particle duality of matter by de-Broglie, which of the following graph plot presents most appropriate relationship between wavelength of electron (\lambda) and momentum of electron (p) ?

Structure of Atom PYQ — JEE Main 2024 · 1 Feb · Shift 1 · Q13 with Solution

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Correct answer: D

Use de-Broglie relation

According to de-Broglie wave-particle duality,
$\lambda = \frac{h}{p}$
where:
- $\lambda$ = wavelength of electron
- $p$ = momentum of electron
- $h$ = Planck's constant
Understand the relation between $\lambda$ and $p$

Since
$\lambda \propto \frac{1}{p}$
wavelength is inversely proportional to momentum.
Nature of the graph

The graph of
$\lambda = \frac{h}{p}$
is a rectangular hyperbola in the first quadrant:
- as $p$ increases, $\lambda$ decreases,
- it does not form a straight line,
- it approaches both axes asymptotically.
Choose the correct plot

Therefore, the correct graph must show an inverse relation between $\lambda$ and $p$ .

Hence, Option D is the most appropriate.
Comparison with stored answer

Stored correct answer = D

Derived answer = D

So, they match.