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Structure of Atom question

2024 · 8 Apr · Shift 2 · Q29
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Structure of Atom question

2024 · 8 Apr · Shift 2 · Q29

JEE MainChemistryStructure of AtomNumerical+4 / −1
Wavenumber for a radiation having 5800 Ao\mathop A\limits^oAo​ wavelength is x×10 cm−1x \times 10 \mathrm{~cm}^{-1}x×10 cm−1 The value of xxx is ‾\underline{\hspace{2cm}}​. (Integer answer)
Numerical answer
View written solutionFree

Correct answer: 1724

  1. Given wavelength

    The wavelength is λ=5800 A˚\lambda = 5800\,\text{\AA}λ=5800A˚

  2. Convert angstrom to cm

    We know: 1 A˚=10−8 cm1\,\text{\AA} = 10^{-8}\,\text{cm}1A˚=10−8cm

    Therefore, λ=5800×10−8 cm=5.8×10−5 cm\lambda = 5800 \times 10^{-8}\,\text{cm} = 5.8 \times 10^{-5}\,\text{cm}λ=5800×10−8cm=5.8×10−5cm

  3. Use formula for wavenumber

    Wavenumber is νˉ=1λ\bar\nu = \frac{1}{\lambda}νˉ=λ1​

    So, νˉ=15.8×10−5 cm−1\bar\nu = \frac{1}{5.8 \times 10^{-5}}\,\text{cm}^{-1}νˉ=5.8×10−51​cm−1

  4. Calculate

    νˉ=15.8×105\bar\nu = \frac{1}{5.8} \times 10^5νˉ=5.81​×105 νˉ≈0.1724×105=1.724×104 cm−1\bar\nu \approx 0.1724 \times 10^5 = 1.724 \times 10^4\,\text{cm}^{-1}νˉ≈0.1724×105=1.724×104cm−1

  5. Match with the given form

    Given: νˉ=x×10 cm−1\bar\nu = x \times 10\,\text{cm}^{-1}νˉ=x×10cm−1

    So, 1.724×104=x×101.724 \times 10^4 = x \times 101.724×104=x×10

    x=1.724×10410=1724x = \frac{1.724 \times 10^4}{10} = 1724x=101.724×104​=1724

  6. Final answer

    1724\boxed{1724}1724​

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