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Structure of Atom question

2020 · 8 Jan · Shift 1 · Q6
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Structure of Atom question

2020 · 8 Jan · Shift 1 · Q6

JEE MainChemistryStructure of AtomMCQ+4 / −1
For the Balmer series in the spectrum of H atom, u‾=RH{1n12−1n22}\overline u = {R_H}\left\{ {{1 \over {n_1^2}} - {1 \over {n_2^2}}} \right\}u=RH​{n12​1​−n22​1​}, the correct statements among (I) to (IV) are : (I) As wavelength decreases, the lines in the series converge (II) The integer n1 is equal to 2 (III) The lines of longest wavelength corresponds to n2 = 3 (IV) The ionization energy of hydrogen can be calculated from wave number of these lines
  1. A
    (II), (III), (IV)
  2. B
    (I), (II), (III)
  3. C
    (I), (III), (IV)
  4. D
    (I), (II), (IV)
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