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Structure of Atom question

2020 · 7 Jan · Shift 1 · Q5
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Structure of Atom question

2020 · 7 Jan · Shift 1 · Q5

JEE MainChemistryStructure of AtomMCQ+4 / −1
The number of orbitals associated with quantum number n = 5, ms = +12{1 \over 2}21​ is :
  1. A
    11
  2. B
    25
  3. C
    15
  4. D
    50
View written solutionFree

Correct answer: B

  1. For a given principal quantum number n=5n=5n=5, the allowed values of azimuthal quantum number are l=0,1,2,3,4l=0,1,2,3,4l=0,1,2,3,4

  2. For each lll, the number of orbitals is given by 2l+12l+12l+1 So total number of orbitals in the shell n=5n=5n=5 is ∑l=04(2l+1)=1+3+5+7+9=25\sum_{l=0}^{4}(2l+1)=1+3+5+7+9=25∑l=04​(2l+1)=1+3+5+7+9=25

  3. The magnetic spin quantum number ms=+12m_s=+\frac{1}{2}ms​=+21​ specifies the spin of an electron, not the orbital itself. Orbitals are determined by nnn, lll, and mlm_lml​ only.

Hence, the number of orbitals associated with n=5n=5n=5 remains 252525

  1. Therefore, the correct option is: 25\boxed{25}25​ which is option B\boxed{B}B​.

  2. Comparison with stored answer: The stored correct answer is BBB, which matches our derived answer.

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