JEE MainChemistryStructure of AtomMCQ+4 / −1
The shortest wavelength of atom in the Lyman series is 1. The longest wavelength in the Balmar series of is :
- A
- B
- C
- D
View written solutionFree
Correct answer: D
- Use the Rydberg formula
For a hydrogen-like species,
where is the atomic number.
- Find : shortest wavelength of H atom in Lyman series
For hydrogen, .
In the Lyman series, transitions end at . The shortest wavelength corresponds to the largest energy gap, i.e. .
So,
Hence,
- Find the longest wavelength in Balmer series of
For , .
In the Balmer series, transitions end at . The longest wavelength corresponds to the smallest energy gap, so take the nearest higher level:
Thus,
So,
But since
we get
- Match with the options
So the correct option is:
D
- Comparison with stored answer
Stored correct answer: D
Our derived answer: D
They match.
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