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Some Basic Concepts of Chemistry question

2024 · 30 Jan · Shift 2 · Q8
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Some Basic Concepts of Chemistry question

2024 · 30 Jan · Shift 2 · Q8

JEE MainChemistrySome Basic Concepts of ChemistryMCQ+4 / −1
If a substance 'AAA' dissolves in solution of a mixture of 'BBB' and 'CCC' with their respective number of moles as nA,nB\mathrm{n}_{\mathrm{A}}, \mathrm{n}_{\mathrm{B}}nA​,nB​ and nC3\mathrm{n}_{\mathrm{C}_3}nC3​​. Mole fraction of C\mathrm{C}C in the solution is
  1. A
    nCnA×nB×nC\frac{n_C}{n_A \times n_B \times n_C}nA​×nB​×nC​nC​​
  2. B
    nBnA+nB\frac{n_B}{n_A+n_B}nA​+nB​nB​​
  3. C
    nCnA+nB+nC\frac{n_C}{n_A+n_B+n_C}nA​+nB​+nC​nC​​
  4. D
    nCnA−nB−nC\frac{n_C}{n_A-n_B-n_C}nA​−nB​−nC​nC​​
View written solutionFree

Correct answer: C

  1. Recall the definition of mole fraction

    For any component in a solution, xi=moles of component itotal moles of all componentsx_i = \frac{\text{moles of component } i}{\text{total moles of all components}}xi​=total moles of all componentsmoles of component i​

  2. Identify the components present

    The solution contains three substances: AAA, BBB, and CCC.

    Their moles are: nA,  nB,  nCn_A,\; n_B,\; n_CnA​,nB​,nC​

  3. Write total number of moles

    ntotal=nA+nB+nCn_{\text{total}} = n_A + n_B + n_Cntotal​=nA​+nB​+nC​

  4. Mole fraction of CCC

    Therefore, the mole fraction of CCC is xC=nCnA+nB+nCx_C = \frac{n_C}{n_A + n_B + n_C}xC​=nA​+nB​+nC​nC​​

  5. Match with the options

    • A: nCnA×nB×nC\frac{n_C}{n_A \times n_B \times n_C}nA​×nB​×nC​nC​​ ❌ incorrect
    • B: nBnA+nB\frac{n_B}{n_A+n_B}nA​+nB​nB​​ ❌ this is not mole fraction of CCC
    • C: nCnA+nB+nC\frac{n_C}{n_A+n_B+n_C}nA​+nB​+nC​nC​​ ✅ correct
    • D: nCnA−nB−nC\frac{n_C}{n_A-n_B-n_C}nA​−nB​−nC​nC​​ ❌ incorrect
  6. Final answer

    The correct option is: C\boxed{\text{C}}C​

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