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Some Basic Concepts of Chemistry question

2023 · 25 Jan · Shift 1 · Q8
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Some Basic Concepts of Chemistry question

2023 · 25 Jan · Shift 1 · Q8

JEE MainChemistrySome Basic Concepts of ChemistryMCQ+4 / −1
'25 volume' hydrogen peroxide means
  1. A
    1 L marketed solution contains 75 g of H 2_22​ O 2_22​.
  2. B
    1 L marketed solution contains 250 g of H 2_22​ O 2_22​.
  3. C
    1 L marketed solution contains 25 g of H 2_22​ O 2_22​.
  4. D
    100 mL marketed solution contains 25 g of H 2_22​ O 2_22​.
View written solutionFree

Correct answer: A

  1. Meaning of volume strength

For hydrogen peroxide, $x$-volume means:

1 volume of solution gives xxx volumes of O2O_2O2​ gas at NTP on decomposition.

So, 25-volume H2O2H_2O_2H2​O2​ means:

1 L solution→25 L O2 at NTP1\,\text{L solution} \rightarrow 25\,\text{L } O_2 \text{ at NTP}1L solution→25L O2​ at NTP


  1. Decomposition reaction

2H2O2→2H2O+O22H_2O_2 \rightarrow 2H_2O + O_22H2​O2​→2H2​O+O2​

From the equation:

  • 2 mol$ $H_2O_2$ produce $1 mol O2O_2O2​

At NTP, 1 mol gas occupies 22.4 L22.4\,\text{L}22.4L.

So, 22.4 L22.4\,\text{L}22.4L of O2O_2O2​ are produced by 2 mol of H2O2H_2O_2H2​O2​.

Mass of 2 mol H2O2H_2O_2H2​O2​:

2×34=68 g2 \times 34 = 68\,\text{g}2×34=68g

Thus,

22.4 L O2↔68 g H2O222.4\,\text{L } O_2 \leftrightarrow 68\,\text{g } H_2O_222.4L O2​↔68g H2​O2​


  1. For 25 L of O2O_2O2​

Required mass of H2O2H_2O_2H2​O2​ is:

Mass=6822.4×25\text{Mass} = \frac{68}{22.4} \times 25Mass=22.468​×25

=75.89 g≈75 g= 75.89\,\text{g} \approx 75\,\text{g}=75.89g≈75g

So, 1 L of marketed solution contains about 75 g of H2O2H_2O_2H2​O2​.


  1. Check options
  • A: 1 L marketed solution contains 75 g of H2O2H_2O_2H2​O2​ ✅
  • B: 250 g in 1 L ❌
  • C: 25 g in 1 L ❌
  • D: 25 g in 100 mL means 250 g in 1 L ❌

  1. Final answer

The correct option is:

A\boxed{\text{A}}A​

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