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Some Basic Concepts of Chemistry question

2023 · 25 Jan · Shift 1 · Q18

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Some Basic Concepts of Chemistry
2023 · 25 Jan · Shift 1 · Q18

Some Basic Concepts of Chemistry question

2023 · 25 Jan · Shift 1 · Q18

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1

In sulphur estimation, 0.471 g of an organic compound gave 1.4439 g of barium sulphate. The percentage of sulphur in the compound is

\underline{\hspace{2cm}}

(Nearest Integer) (Given : Atomic mass Ba: 137 u, S: 32 u, O: 16 u)

Numerical answer

View written solutionFree

Correct answer: 42

Find molar mass of $\mathrm{BaSO_4}$

$M(\mathrm{BaSO_4}) = 137 + 32 + 4\times 16 = 137 + 32 + 64 = 233$

Mass of sulphur present in $1.4439\,$ g of $\mathrm{BaSO_4}$

In $233\,$ g of $\mathrm{BaSO_4}$ , mass of sulphur $= 32\,$ g.

So, in $1.4439\,$ g of $\mathrm{BaSO_4}$ , mass of sulphur is

$m_S = 1.4439\times \frac{32}{233}$

$m_S = 0.1984\,\text{g}$

Percentage of sulphur in the organic compound

Mass of organic compound $= 0.471\,$ g.

$\%S = \frac{0.1984}{0.471}\times 100$

$\%S \approx 42.12\%$

Nearest integer

$\boxed{42}$

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