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Some Basic Concepts of Chemistry question

2023 · 11 Apr · Shift 1 · Q16
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Some Basic Concepts of Chemistry question

2023 · 11 Apr · Shift 1 · Q16

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1
A solution of sugar is obtained by mixing 200 g200 \mathrm{~g}200 g of its 25%25 \%25% solution and 500 g500 \mathrm{~g}500 g of its 40%40 \%40% solution (both by mass). The mass percentage of the resulting sugar solution is ‾\underline{\hspace{2cm}}​ (Nearest integer)
Numerical answer
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Correct answer: 36

  1. Find sugar in each solution

    • From 200 g200\,\text{g}200g of 25%25\%25% sugar solution: Sugar=25100×200=50 g\text{Sugar} = \frac{25}{100}\times 200 = 50\,\text{g}Sugar=10025​×200=50g

    • From 500 g500\,\text{g}500g of 40%40\%40% sugar solution: Sugar=40100×500=200 g\text{Sugar} = \frac{40}{100}\times 500 = 200\,\text{g}Sugar=10040​×500=200g

  2. Find total sugar and total solution mass

    • Total sugar: 50+200=250 g50 + 200 = 250\,\text{g}50+200=250g

    • Total mass of solution: 200+500=700 g200 + 500 = 700\,\text{g}200+500=700g

  3. Calculate mass percentage of sugar in the final solution

    Mass % of sugar=250700×100\text{Mass \% of sugar} = \frac{250}{700}\times 100Mass % of sugar=700250​×100

    =35.714%= 35.714\%=35.714%

  4. Nearest integer

    35.714≈3635.714 \approx 3635.714≈36

Therefore, the mass percentage of the resulting sugar solution is 363636.

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