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Some Basic Concepts of Chemistry question

2023 · 10 Apr · Shift 2 · Q5
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  5. /2023 · 10 Apr · Shift 2 · Q5

Some Basic Concepts of Chemistry question

2023 · 10 Apr · Shift 2 · Q5

JEE MainChemistrySome Basic Concepts of ChemistryMCQ+4 / −1
Given below are two statements: one is labelled as Assertion A\mathbf{A}A and the other is labelled as Reason R\mathbf{R}R Assertion A : 3.1500 g3.1500 \mathrm{~g}3.1500 g of hydrated oxalic acid dissolved in water to make 250.0 mL250.0 \mathrm{~mL}250.0 mL solution will result in 0.1 M0.1 \mathrm{~M}0.1 M oxalic acid solution. Reason R\mathbf{R}R: Molar mass of hydrated oxalic acid is 126 g mol−1126 \mathrm{~g} \mathrm{~mol}^{-1}126 g mol−1 In the light of the above statements, choose the correct answer from the options given below.
  1. A
    Both A and R are true but R is NOT the correct explanation of A
  2. B
    A is true but R is false
  3. C
    Both A and R are true and R is the correct explanation of A
  4. D
    A is false but R is true
View written solutionFree

Correct answer: C

  1. Identify the compound

    Hydrated oxalic acid is oxalic acid dihydrate: H2C2O4⋅2H2O\mathrm{H_2C_2O_4\cdot 2H_2O}H2​C2​O4​⋅2H2​O

  2. Calculate its molar mass

    M(H2C2O4)=2(1)+2(12)+4(16)=2+24+64=90 g mol−1M(\mathrm{H_2C_2O_4}) = 2(1) + 2(12) + 4(16) = 2 + 24 + 64 = 90\,\mathrm{g\,mol^{-1}}M(H2​C2​O4​)=2(1)+2(12)+4(16)=2+24+64=90gmol−1

    M(2H2O)=2×18=36 g mol−1M(2\mathrm{H_2O}) = 2\times 18 = 36\,\mathrm{g\,mol^{-1}}M(2H2​O)=2×18=36gmol−1

    Therefore, M(H2C2O4⋅2H2O)=90+36=126 g mol−1M(\mathrm{H_2C_2O_4\cdot 2H_2O}) = 90 + 36 = 126\,\mathrm{g\,mol^{-1}}M(H2​C2​O4​⋅2H2​O)=90+36=126gmol−1

    So, Reason R is true.

  3. Find moles in 3.1500 g hydrated oxalic acid

    n=3.1500126=0.0250 moln = \frac{3.1500}{126} = 0.0250\,\mathrm{mol}n=1263.1500​=0.0250mol

  4. Find molarity of the solution

    Volume of solution: 250.0 mL=0.2500 L250.0\,\mathrm{mL} = 0.2500\,\mathrm{L}250.0mL=0.2500L

    Molarity: M=nV=0.02500.2500=0.100 MM = \frac{n}{V} = \frac{0.0250}{0.2500} = 0.100\,\mathrm{M}M=Vn​=0.25000.0250​=0.100M

    Hence, Assertion A is true.

  5. Check whether R explains A

    The assertion is proved directly using the molar mass of hydrated oxalic acid: Molarity=3.15001260.2500=0.1 M\text{Molarity} = \frac{\frac{3.1500}{126}}{0.2500} = 0.1\,\mathrm{M}Molarity=0.25001263.1500​​=0.1M

    Therefore, the reason correctly explains the assertion.

  6. Final conclusion

    • Assertion A: True
    • Reason R: True
    • R is the correct explanation of A

    So the correct option is C.

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