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Some Basic Concepts of Chemistry question

2023 · 13 Apr · Shift 2 · Q16
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Some Basic Concepts of Chemistry question

2023 · 13 Apr · Shift 2 · Q16

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1
1 g1 \mathrm{~g}1 g of a carbonate (M2CO3)\left(\mathrm{M}_{2} \mathrm{CO}_{3}\right)(M2​CO3​) on treatment with excess HCl\mathrm{HCl}HCl produces 0.01 mol0.01 \mathrm{~mol}0.01 mol of CO2\mathrm{CO}_{2}CO2​. The molar mass of M2CO3\mathrm{M}_{2} \mathrm{CO}_{3}M2​CO3​ is ‾\underline{\hspace{2cm}}​g mol−1\mathrm{g} ~\mathrm{mol}^{-1}g mol−1. (Nearest integer)
Numerical answer
View written solutionFree

Correct answer: 100

  1. Write the reaction

    A carbonate reacts with excess hydrochloric acid as: M2CO3+2HCl→2MCl+H2O+CO2\mathrm{M_2CO_3 + 2HCl \rightarrow 2MCl + H_2O + CO_2}M2​CO3​+2HCl→2MCl+H2​O+CO2​

  2. Use stoichiometry

    From the reaction, 1 mol M2CO3→1 mol CO21 \text{ mol } \mathrm{M_2CO_3} \rightarrow 1 \text{ mol } \mathrm{CO_2}1 mol M2​CO3​→1 mol CO2​

    Given that 0.010.010.01 mol of CO2\mathrm{CO_2}CO2​ is produced, moles of M2CO3\mathrm{M_2CO_3}M2​CO3​ are also: n(M2CO3)=0.01 moln(\mathrm{M_2CO_3}) = 0.01 \text{ mol}n(M2​CO3​)=0.01 mol

  3. Calculate molar mass

    We are given mass of carbonate = 1 g1\,\mathrm{g}1g.

    Using Molar mass=massmoles\text{Molar mass} = \frac{\text{mass}}{\text{moles}}Molar mass=molesmass​

    Molar mass of M2CO3=10.01=100 g mol−1\text{Molar mass of } \mathrm{M_2CO_3} = \frac{1}{0.01} = 100\,\mathrm{g\,mol^{-1}}Molar mass of M2​CO3​=0.011​=100gmol−1

  4. Nearest integer

    100\boxed{100}100​

  5. Compare with stored answer

    Stored correct answer = 100100100.

    My derived answer matches the stored answer.

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