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Some Basic Concepts of Chemistry question

2023 · 11 Apr · Shift 2 · Q9
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Some Basic Concepts of Chemistry question

2023 · 11 Apr · Shift 2 · Q9

JEE MainChemistrySome Basic Concepts of ChemistryMCQ+4 / −1
A solution is prepared by adding 2 g2 \mathrm{~g}2 g of "X\mathrm{X}X" to 1 mole of water. Mass percent of "X\mathrm{X}X" in the solution is :
  1. A
    20%
  2. B
    10%
  3. C
    2%
  4. D
    5%
View written solutionFree

Correct answer: B

  1. Given data

    • Mass of solute X=2 gX = 2\,\text{g}X=2g
    • Water = 111 mole

  2. Mass of water Since molar mass of water is 18 g mol−118\,\text{g mol}^{-1}18g mol−1, 1 mole of water=18 g1\text{ mole of water} = 18\,\text{g}1 mole of water=18g

  3. Total mass of solution Mass of solution=mass of solute+mass of solvent=2+18=20 g\text{Mass of solution} = \text{mass of solute} + \text{mass of solvent} = 2 + 18 = 20\,\text{g}Mass of solution=mass of solute+mass of solvent=2+18=20g

  4. Mass percent of solute XXX Mass % of X=mass of Xmass of solution×100\text{Mass \% of }X = \frac{\text{mass of }X}{\text{mass of solution}} \times 100Mass % of X=mass of solutionmass of X​×100 =220×100=10%= \frac{2}{20}\times 100 = 10\%=202​×100=10%

  5. Option check

    • A: 20%20\%20% ❌
    • B: 10%10\%10% ✅
    • C: 2%2\%2% ❌
    • D: 5%5\%5% ❌

Therefore, the correct answer is B: 10%10\%10%.

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