JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1
The number of atoms in 8g of sodium is x 1023. The value of x is . (Nearest integer) [Given : NA = 6.02 1023 mol 1 Atomic mass of Na = 23.0 u]
Numerical answer
View written solutionFree
Correct answer: 2
-
Find moles of sodium in
Molar mass of sodium
-
Find number of atoms
Number of atoms
-
Calculate the numerical value
-
Compare with the form
So,
Nearest integer:
-
Verification with stored answer
Derived answer
Stored correct answer
Hence, they agree.
More from Some Basic Concepts of Chemistry
- If 80 g of copper sulphate . 5 is dissolved in deionised water to make 5L of solution. The concentration of the copper sulphate solution is x 10 3 mol L 1. The value of x is .…2021 · Numerical
- Complete combustion of 750 g of an organic compound provides 420 g of and 210 g of . The percentage composition of carbon and hydrogen in organic compound is 15.3 and respectively. (Round off to the…2021 · Numerical
- If the above equation is balanced with integer coefficients, the value of c is . (Round off to the Nearest Integer).2021 · Numerical
- A 6.50 molal solution of KOH (aq.) has a density of 1.89 g cm 3. The molarity of the solution is mol dm 3. (Round off to the Nearest Integer). [Atomic masses : K : 39.0 u; O : 16.0 u; H : 1.0 u]2021 · Numerical
- When 35 mL of 0.15 M lead nitrate solution is mixed with 20 mL of 0.12 M chromic sulphate solution, 10 5 moles of lead sulphate precipitate out. (Round off to the Nearest Integer).2021 · Numerical
- The exact volumes of 1 M solution required to neutralise 50 mL of 1 M solution and 100 mL of 2 M solution, respectively, are :2021 · MCQ
- 15 mL of aqueous solution of in acidic medium completely reacted with 20 mL of 0.03 M aqueous . The molarity of the solution is 10-2 M. (Round off to the Nearest…2021 · Numerical
- The mole fraction of a solute in a 100 molal aqueous solution is 10 2. (Round off to the Nearest Integer). [Given : Atomic masses : H : 1.0 u, O : 16.0 u ]2021 · Numerical