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Some Basic Concepts of Chemistry question

2021 · 1 Sep · Shift 2 · Q18
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Some Basic Concepts of Chemistry question

2021 · 1 Sep · Shift 2 · Q18

JEE MainChemistrySome Basic Concepts of ChemistryNumerical+4 / −1
The number of atoms in 8g of sodium is x ×\times× 1023. The value of x is ‾\underline{\hspace{2cm}}​. (Nearest integer) [Given : NA = 6.02 ×\times× 1023 mol −-− 1 Atomic mass of Na = 23.0 u]
Numerical answer
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Correct answer: 2

  1. Find moles of sodium in 8 g8\text{ g}8 g

    Molar mass of sodium =23 g mol−1= 23\text{ g mol}^{-1}=23 g mol−1

    n=given massmolar mass=823 moln = \frac{\text{given mass}}{\text{molar mass}} = \frac{8}{23}\text{ mol}n=molar massgiven mass​=238​ mol

  2. Find number of atoms

    Number of atoms =nNA= nN_A=nNA​

    N=823×6.02×1023N = \frac{8}{23}\times 6.02\times 10^{23}N=238​×6.02×1023

  3. Calculate the numerical value

    823≈0.3478\frac{8}{23} \approx 0.3478238​≈0.3478

    N≈0.3478×6.02×1023N \approx 0.3478 \times 6.02 \times 10^{23}N≈0.3478×6.02×1023

    N≈2.09×1023N \approx 2.09 \times 10^{23}N≈2.09×1023

  4. Compare with the form x×1023x \times 10^{23}x×1023

    So,

    x≈2.09x \approx 2.09x≈2.09

    Nearest integer:

    x=2x = 2x=2

  5. Verification with stored answer

    Derived answer =2= 2=2

    Stored correct answer =2= 2=2

    Hence, they agree.

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