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Solutions question

2020 · 8 Jan · Shift 1 · Q2
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Solutions question

2020 · 8 Jan · Shift 1 · Q2

JEE MainChemistrySolutionsMCQ+4 / −1
A graph of vapour pressure and temperature for three different liquids X, Y, and Z is shown below : JEE Main 2020 (Online) 8th January Morning Slot Chemistry - Solutions Question 118 English The following inferences are made : (A) X has higher intermolecular interactions compared to Y. (B) X has lower intermolecular interactions compared to Y. (C) Z has lower intermolecular interactions compared to Y. The correct inference (s) is / are :
  1. A
    (B)
  2. B
    (A)
  3. C
    (C)
  4. D
    (A) and (C)
View written solutionFree

Correct answer: A

  1. Key concept: At a given temperature, a liquid with higher vapour pressure is more volatile and therefore has weaker intermolecular forces.

  2. Also, the liquid which reaches a given vapour pressure at a lower temperature has weaker intermolecular interactions.

  3. From the vapour pressure vs temperature graph:

    • Curve X lies above Y at the same temperature, so PX>PYP_X > P_YPX​>PY​.
    • Therefore, X has weaker intermolecular forces than Y.
    • Hence inference (B) is correct and (A) is false.
  4. Comparing Z and Y:

    • Curve Z lies below Y at the same temperature, so PZ<PYP_Z < P_YPZ​<PY​.
    • Therefore, Z has stronger intermolecular forces than Y, not lower.
    • Hence inference (C) is false.
  5. Therefore, the only correct inference is: (B)\boxed{(B)}(B)​

  6. Matching with options:

    • Option A: (B)(B)(B)
    • So the correct option is A.
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