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Solutions question

2019 · 8 Apr · Shift 2 · Q1
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Solutions question

2019 · 8 Apr · Shift 2 · Q1

JEE MainChemistrySolutionsMCQ+4 / −1
For the solution of the gases w, x, y and z in water at 298K, the Henrys law constants (KH) are 0.5, 2, 35 and 40 kbar, respectively. The correct plot for the given data is :-
  1. A
    JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Solutions Question 127 English Option 1
  2. B
    JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Solutions Question 127 English Option 2
  3. C
    JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Solutions Question 127 English Option 3
  4. D
    JEE Main 2019 (Online) 8th April Evening Slot Chemistry - Solutions Question 127 English Option 4
View written solutionFree

Correct answer: A

  1. Henry’s law relation

    For a gas dissolved in water, p=KHxp = K_H xp=KH​x where:

    • ppp = partial pressure of gas
    • xxx = mole fraction of gas in solution
    • KHK_HKH​ = Henry’s law constant
  2. Meaning of KHK_HKH​

    From x=pKHx = \frac{p}{K_H}x=KH​p​ we see that for a given pressure, larger KHK_HKH​ means smaller solubility.

    So, solubility order is inverse of KHK_HKH​.

  3. Given values

    • For www: KH=0.5K_H = 0.5KH​=0.5 kbar
    • For xxx: KH=2K_H = 2KH​=2 kbar
    • For yyy: KH=35K_H = 35KH​=35 kbar
    • For zzz: KH=40K_H = 40KH​=40 kbar
  4. Compare solubilities

    Since smaller KHK_HKH​ means greater solubility, w>x>y>zw > x > y > zw>x>y>z in solubility.

  5. Compare slopes if graph is ppp vs xxx

    From p=KHxp = K_H xp=KH​x slope =KH= K_H=KH​.

    Hence slope order is z>y>x>wz > y > x > wz>y>x>w because 40>35>2>0.540 > 35 > 2 > 0.540>35>2>0.5

  6. Correct plot

    Therefore, the correct graph must show straight lines through origin with increasing slope in the order: w<x<y<zw < x < y < zw<x<y<z (in terms of slope), or equivalently, solubility order: w>x>y>zw > x > y > zw>x>y>z

    Thus, the correct option is A.

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