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Solutions question

2019 · 9 Apr · Shift 2 · Q2
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Solutions question

2019 · 9 Apr · Shift 2 · Q2

JEE MainChemistrySolutionsMCQ+4 / −1
Molal depression constant for a solvent is 4.0 kg mol–1. The depression in the freezing point of the solvent for 0.03 mol kg–1 solution of K2SO4K_2SO_4K2​SO4​ is : (Assume complete dissociation of the electrolyte)
  1. A
    0.18 K
  2. B
    0.24 K
  3. C
    0.36 K
  4. D
    0.12 K
View written solutionFree

Correct answer: C

  1. Use the formula for depression in freezing point

    ΔTf=iKfm\Delta T_f = i K_f mΔTf​=iKf​m

    where:

    • iii = van’t Hoff factor
    • Kf=4.0 kg mol−1K_f = 4.0\ \text{kg mol}^{-1}Kf​=4.0 kg mol−1
    • m=0.03 mol kg−1m = 0.03\ \text{mol kg}^{-1}m=0.03 mol kg−1
  2. Find the van’t Hoff factor for K2SO4K_2SO_4K2​SO4​

    Assuming complete dissociation:

    K2SO4→2K++SO42−K_2SO_4 \rightarrow 2K^+ + SO_4^{2-}K2​SO4​→2K++SO42−​

    Total number of ions produced = 333

    Hence,

    i=3i = 3i=3

  3. Substitute into the formula

    ΔTf=3×4.0×0.03\Delta T_f = 3 \times 4.0 \times 0.03ΔTf​=3×4.0×0.03

    ΔTf=0.36 K\Delta T_f = 0.36\ \text{K}ΔTf​=0.36 K

  4. Match with the options

    0.36 K0.36\ \text{K}0.36 K corresponds to Option C.

  5. Comparison with stored correct answer

    Stored correct answer = C

    Derived answer = C

    So they agree.

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