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Solutions question

2017 · 9 Apr · Shift 1 · Q18
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Solutions question

2017 · 9 Apr · Shift 1 · Q18

JEE MainChemistrySolutionsMCQ+4 / −1
A solution is prepared by mixing 8.5 g of CH2Cl2CH_2Cl_2CH2​Cl2​ and 11.95 g of CHCl3CHCl_3CHCl3​ . If vapour pressure of CH2Cl2CH_2Cl_2CH2​Cl2​ and CHCl3CHCl_3CHCl3​ at 298 K are 415 and 200 mmHg respectively, the mole fraction of CHCl3CHCl_3CHCl3​ in vapour form is : (Molar mass of Cl = 35.5 g mol−1)
  1. A
    0.162
  2. B
    0.675
  3. C
    0.325
  4. D
    0.486
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