1. Use Henry’s law

For a gas dissolved in a liquid at constant temperature, the solubility is directly proportional to its partial pressure:

$S \propto P$

So,

$\frac{S_1}{P_1} = \frac{S_2}{P_2}$

2. Given data

• At $P_1 = 500$ torr, $S_1 = 0.01\ \text{g L}^{-1}$
• At $P_2 = 750$ torr, $S_2 = ?$

3. Apply the proportionality

$S_2 = S_1 \cdot \frac{P_2}{P_1}$

$S_2 = 0.01 \times \frac{750}{500}$

$S_2 = 0.01 \times 1.5 = 0.015\ \text{g L}^{-1}$

4. Match with options

$0.015\ \text{g L}^{-1}$

This corresponds to Option B.

5. Comparison with stored answer

Stored correct answer: B

Our derived answer: B

So they agree.