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Solutions question

2014 · Shift 0 · Q2
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Solutions question

2014 · Shift 0 · Q2

JEE MainChemistrySolutionsMCQ+4 / −1
Consider separate solutions of 0.500 M C2H5OHC_2H_5OHC2​H5​OH(aq), 0.100 M Mg3(PO4)2Mg_3(PO_4)_2Mg3​(PO4​)2​(aq), 0.250 M KBrKBrKBr(aq) and 0.125 M Na3PO4Na_3PO_4Na3​PO4​(aq) at 25oC. Which statement is true about these solutions, assuming all salts to be strong electrolytes?
  1. A
    0.125 M Na3PO4Na_3PO_4Na3​PO4​(aq) has the highest osmotic pressure.
  2. B
    0.500 M C2H5OHC_2H_5OHC2​H5​OH(aq) has the highest osmotic pressure
  3. C
    They all have the same osmotic pressure
  4. D
    0.100 M Mg3(PO4)2Mg_3(PO_4)_2Mg3​(PO4​)2​(aq) has the highest osmotic pressure.
View written solutionFree

Correct answer: C

  1. Use the osmotic pressure formula

For dilute solutions, π=iMRT\pi = iMRTπ=iMRT where:

  • π\piπ = osmotic pressure
  • iii = van't Hoff factor
  • MMM = molarity
  • RRR = gas constant
  • TTT = temperature

Since all solutions are at the same temperature (25∘25^\circ25∘C), and R,TR,TR,T are constant, we only need to compare iMiMiM.


  1. Find iii for each solute

(a) 0.500 M  C2H5OH0.500\,M\; C_2H_5OH0.500MC2​H5​OH

Ethanol is a non-electrolyte, so it does not dissociate. i=1i=1i=1 Thus, iM=1×0.500=0.500iM = 1 \times 0.500 = 0.500iM=1×0.500=0.500

(b) 0.100 M  Mg3(PO4)20.100\,M\; Mg_3(PO_4)_20.100MMg3​(PO4​)2​

Assuming complete dissociation: Mg3(PO4)2→3Mg2++2PO43−Mg_3(PO_4)_2 \rightarrow 3Mg^{2+} + 2PO_4^{3-}Mg3​(PO4​)2​→3Mg2++2PO43−​ Total ions =3+2=5= 3+2=5=3+2=5, so i=5i=5i=5 Thus, iM=5×0.100=0.500iM = 5 \times 0.100 = 0.500iM=5×0.100=0.500

(c) 0.250 M  KBr0.250\,M\; KBr0.250MKBr

Strong electrolyte: KBr→K++Br−KBr \rightarrow K^+ + Br^-KBr→K++Br− Total ions =2=2=2, so i=2i=2i=2 Thus, iM=2×0.250=0.500iM = 2 \times 0.250 = 0.500iM=2×0.250=0.500

(d) 0.125 M  Na3PO40.125\,M\; Na_3PO_40.125MNa3​PO4​

Strong electrolyte: Na3PO4→3Na++PO43−Na_3PO_4 \rightarrow 3Na^+ + PO_4^{3-}Na3​PO4​→3Na++PO43−​ Total ions =4=4=4, so i=4i=4i=4 Thus, iM=4×0.125=0.500iM = 4 \times 0.125 = 0.500iM=4×0.125=0.500


  1. Compare osmotic pressures

For all four solutions, iM=0.500iM = 0.500iM=0.500 So, π=iMRT\pi = iMRTπ=iMRT will be the same for all.


  1. Evaluate options
  • A: False
  • B: False
  • C: True
  • D: False

So the correct option is: C\boxed{C}C​


  1. Comparison with stored correct answer

Stored correct answer: C

My derived answer: C

They agree.

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