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Salt Analysis question

2024 · 8 Apr · Shift 1 · Q10
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Salt Analysis question

2024 · 8 Apr · Shift 1 · Q10

JEE MainChemistrySalt AnalysisMCQ+4 / −1

Match List I with List II

LIST I
(Name of the test)		 LIST II
(Reaction sequence involved) [M is metal]
A. Borax bead test I. MCO3→MO→+ΔCo(NO3)2CoO⋅MO\mathrm{MCO}_3 \rightarrow \mathrm{MO} \xrightarrow[+\Delta]{\mathrm{Co}\left(\mathrm{NO}_3\right)_2} \mathrm{CoO} \cdot \mathrm{MO}MCO3​→MOCo(NO3​)2​+Δ​CoO⋅MO
B. Charcoal cavity test II. MCO3→MCl2→M2+\mathrm{MCO}_3 \rightarrow \mathrm{MCl}_2 \rightarrow \mathrm{M}^{2+}MCO3​→MCl2​→M2+
C. Cobalt nitrate test III. MSO4→ΔNa2 B4O7M(BO2)2→MBO2→M\mathrm{MSO}_4 \xrightarrow[\Delta]{\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7} \mathrm{M}\left(\mathrm{BO}_2\right)_2 \rightarrow \mathrm{MBO}_2 \rightarrow \mathrm{M}MSO4​Na2​ B4​O7​Δ​M(BO2​)2​→MBO2​→M
D. Flame test IV. MSO4→ΔNa2CO3MCO3→MO→M\mathrm{MSO}_4 \xrightarrow[\Delta]{\mathrm{Na}_2 \mathrm{CO}_3} \mathrm{MCO}_3 \rightarrow \mathrm{MO} \rightarrow \mathrm{M}MSO4​Na2​CO3​Δ​MCO3​→MO→M

Choose the correct answer from the options given below:

  1. A
    A-III, B-I, C-IV, D-II
  2. B
    A-III, B-IV, C-I, D-II
  3. C
    A-III, B-II, C-IV, D-I
  4. D
    A-III, B-I, C-II, D-IV
View written solutionFree

Correct answer: B

  1. Identify each qualitative test and its reaction pattern

We match the tests in List I with the reaction sequences in List II.

  1. A. Borax bead test

In borax bead test, on heating borax forms boric anhydride, which reacts with metal salt to form a metaborate. On strong heating/reducing flame, it may further reduce.

The given sequence: MSO4→ΔNa2B4O7M(BO2)2→MBO2→M\mathrm{MSO}_4 \xrightarrow[\Delta]{\mathrm{Na}_2\mathrm{B}_4\mathrm{O}_7} \mathrm{M}(\mathrm{BO}_2)_2 \rightarrow \mathrm{MBO}_2 \rightarrow \mathrm{M}MSO4​Na2​B4​O7​Δ​M(BO2​)2​→MBO2​→M corresponds to the borax bead test.

So, A→IIIA \to IIIA→III

  1. B. Charcoal cavity test

In charcoal cavity test, the metal salt is generally mixed with sodium carbonate and heated in a cavity on charcoal. The usual sequence is:

  • metal sulfate to carbonate,
  • carbonate to oxide,
  • oxide to metal.

This matches: MSO4→ΔNa2CO3MCO3→MO→M\mathrm{MSO}_4 \xrightarrow[\Delta]{\mathrm{Na}_2\mathrm{CO}_3} \mathrm{MCO}_3 \rightarrow \mathrm{MO} \rightarrow \mathrm{M}MSO4​Na2​CO3​Δ​MCO3​→MO→M Thus, B→IVB \to IVB→IV

  1. C. Cobalt nitrate test

In cobalt nitrate test, the substance is first converted to oxide by heating, then treated with cobalt nitrate and reheated to form a colored mixed oxide such as: CoO⋅MO\mathrm{CoO} \cdot \mathrm{MO}CoO⋅MO This matches: MCO3→MO→+ΔCo(NO3)2CoO⋅MO\mathrm{MCO}_3 \rightarrow \mathrm{MO} \xrightarrow[+\Delta]{\mathrm{Co}(\mathrm{NO}_3)_2} \mathrm{CoO}\cdot \mathrm{MO}MCO3​→MOCo(NO3​)2​+Δ​CoO⋅MO Hence, C→IC \to IC→I

  1. D. Flame test

In flame test, the salt is converted into volatile chlorides using HCl, and then the metal ion imparts characteristic flame color.

This matches: MCO3→MCl2→M2+\mathrm{MCO}_3 \rightarrow \mathrm{MCl}_2 \rightarrow \mathrm{M}^{2+}MCO3​→MCl2​→M2+ So, D→IID \to IID→II

  1. Final matching

Thus the correct matching is: A−III,  B−IV,  C−I,  D−IIA-III,\; B-IV,\; C-I,\; D-IIA−III,B−IV,C−I,D−II

This corresponds to Option B.

  1. Comparison with stored answer

Stored correct answer = B

Our derived answer = B

So they agree.

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