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Salt Analysis question

2024 · 6 Apr · Shift 1 · Q8
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Salt Analysis question

2024 · 6 Apr · Shift 1 · Q8

JEE MainChemistrySalt AnalysisMCQ+4 / −1

Match List I with List II

LIST I
(Precipitating reagent and conditions)		 LIST II
(Cation)
A.
NH4Cl+NH4OH\mathrm{NH}_4 \mathrm{Cl}+\mathrm{NH}_4 \mathrm{OH}NH4​Cl+NH4​OH
 I. Mn2+\mathrm{Mn^{2+}}Mn2+
B.
NH4OH+Na2CO3\mathrm{NH}_4 \mathrm{OH}+\mathrm{Na}_2 \mathrm{CO}_3NH4​OH+Na2​CO3​
 II. Pb2+\mathrm{Pb^{2+}}Pb2+
C.
NH4OH+NH4Cl+H2 S gas \mathrm{NH}_4 \mathrm{OH}+\mathrm{NH}_4 \mathrm{Cl}+\mathrm{H}_2 \mathrm{~S} \text { gas }NH4​OH+NH4​Cl+H2​ S gas 
 III. Al3+\mathrm{Al^{3+}}Al3+
D. dilute HCl\mathrm{HCl}HCl IV. Sr2+\mathrm{Sr^{2+}}Sr2+

Choose the correct answer from the options given below:

  1. A
    A-III, B-IV, C-I, D-II
  2. B
    A-III, B-IV, C-II, D-I
  3. C
    A-IV, B-III, C-II, D-I
  4. D
    A-IV, B-III, C-I, D-II
View written solutionFree

Correct answer: A

  1. Identify the group reagents in qualitative analysis

    We match each reagent/condition with the cation that gets precipitated under those conditions.

    • Dilute HCl\mathrm{HCl}HCl precipitates Group I cations as chlorides.
    • NH4Cl+NH4OH\mathrm{NH_4Cl + NH_4OH}NH4​Cl+NH4​OH precipitates Group III cations as hydroxides.
    • NH4OH+NH4Cl+H2S\mathrm{NH_4OH + NH_4Cl + H_2S}NH4​OH+NH4​Cl+H2​S precipitates Group IV cations as sulfides in ammoniacal medium.
    • NH4OH+Na2CO3\mathrm{NH_4OH + Na_2CO_3}NH4​OH+Na2​CO3​ precipitates Group V cations as carbonates.

  2. Match each item

    A. NH4Cl+NH4OH\mathrm{NH_4Cl + NH_4OH}NH4​Cl+NH4​OH

    This is the reagent for precipitating Group III hydroxides.

    Among the given cations:

    • Al3+\mathrm{Al^{3+}}Al3+ precipitates as Al(OH)3\mathrm{Al(OH)_3}Al(OH)3​.

    So, A→IIIA \to IIIA→III

    B. NH4OH+Na2CO3\mathrm{NH_4OH + Na_2CO_3}NH4​OH+Na2​CO3​

    This precipitates alkaline earth metals of Group V as carbonates.

    Among the given cations:

    • Sr2+\mathrm{Sr^{2+}}Sr2+ precipitates as SrCO3\mathrm{SrCO_3}SrCO3​.

    So, B→IVB \to IVB→IV

    C. NH4OH+NH4Cl+H2S\mathrm{NH_4OH + NH_4Cl + H_2S}NH4​OH+NH4​Cl+H2​S gas

    In ammoniacal medium, H2S\mathrm{H_2S}H2​S precipitates Group IV metal sulfides.

    Among the given cations:

    • Mn2+\mathrm{Mn^{2+}}Mn2+ precipitates as MnS\mathrm{MnS}MnS.

    So, C→IC \to IC→I

    D. dilute HCl\mathrm{HCl}HCl

    Dilute hydrochloric acid precipitates Group I cations as insoluble chlorides.

    Among the given cations:

    • Pb2+\mathrm{Pb^{2+}}Pb2+ precipitates as PbCl2\mathrm{PbCl_2}PbCl2​.

    So, D→IID \to IID→II

  3. Final matching

    A−III,  B−IV,  C−I,  D−IIA-III,\; B-IV,\; C-I,\; D-IIA−III,B−IV,C−I,D−II

  4. Compare with options

    This corresponds to Option A.

  5. Verification with stored answer

    Stored correct answer: A

    Our derived answer also is A, so they agree.

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