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Redox Reactions question

2024 · 6 Apr · Shift 2 · Q5
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  5. /2024 · 6 Apr · Shift 2 · Q5

Redox Reactions question

2024 · 6 Apr · Shift 2 · Q5

JEE MainChemistryRedox ReactionsMCQ+4 / −1

Match List I with List II.

LIST I
Reaction
LIST II
Type of redox reaction
A.
N2( g)+O2( g)→2NO(g)\mathrm{N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} \rightarrow 2 \mathrm{NO}_{(\mathrm{g})}N2( g)​+O2( g)​→2NO(g)​

I. Decomposition
B.
2 Pb(NO3)2( s)→2PbO(s)+4NO2( g)+O2( g)2 \mathrm{~Pb}\left(\mathrm{NO}_3\right)_{2(\mathrm{~s})} \rightarrow 2 \mathrm{PbO}_{(\mathrm{s})}+4 \mathrm{NO}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})}2 Pb(NO3​)2( s)​→2PbO(s)​+4NO2( g)​+O2( g)​

II. Displacement
C.
2Na(s)+2H2O(l)→2NaOH(aq.)+H2( g)2 \mathrm{Na}_{(\mathrm{s})}+2 \mathrm{H}_2 \mathrm{O}_{(\mathrm{l})} \rightarrow 2 \mathrm{NaOH}_{(\mathrm{aq} .)}+\mathrm{H}_{2(\mathrm{~g})}2Na(s)​+2H2​O(l)​→2NaOH(aq.)​+H2( g)​

III. Disproportionation
D.
2NO2( g)+2−OH( aq. )→NO2(aq.)−+NO3( aq. )−+H2O(l)2 \mathrm{NO}_{2(\mathrm{~g})}+2^{-} \mathrm{OH}(\text { aq. }) \rightarrow \mathrm{NO}_{2(\mathrm{aq} .)}^{-}+\mathrm{NO}_{3(\text { aq. })}^{-}+\mathrm{H}_2 \mathrm{O}_{(\mathrm{l})}2NO2( g)​+2−OH( aq. )→NO2(aq.)−​+NO3( aq. )−​+H2​O(l)​

IV. Combination

Choose the correct answer from the options given below :

  1. A
    (A)-(IV), (B)-(I), (C)-(II), (D)-(III)
  2. B
    (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
  3. C
    (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
  4. D
    (A)-(III), (B)-(II), (C)-(I), (D)-(IV)
View written solutionFree

Correct answer: A

  1. Identify the type of each reaction in List I

A. N2(g)+O2(g)→2NO(g)\mathrm{N_2(g) + O_2(g) \rightarrow 2NO(g)}N2​(g)+O2​(g)→2NO(g)

Two reactants combine to form a single product type.

  • This is a combination reaction.

So, A→IVA \rightarrow IVA→IV


B. 2Pb(NO3)2(s)→2PbO(s)+4NO2(g)+O2(g)2\mathrm{Pb(NO_3)_2(s)} \rightarrow 2\mathrm{PbO(s)} + 4\mathrm{NO_2(g)} + \mathrm{O_2(g)}2Pb(NO3​)2​(s)→2PbO(s)+4NO2​(g)+O2​(g)

A single compound breaks into simpler substances.

  • This is a decomposition reaction.

So, B→IB \rightarrow IB→I


C. 2Na(s)+2H2O(l)→2NaOH(aq)+H2(g)2\mathrm{Na(s)} + 2\mathrm{H_2O(l)} \rightarrow 2\mathrm{NaOH(aq)} + \mathrm{H_2(g)}2Na(s)+2H2​O(l)→2NaOH(aq)+H2​(g)

Sodium displaces hydrogen from water.

  • This is a displacement reaction.

So, C→IIC \rightarrow IIC→II


D. 2NO2(g)+2OH−(aq)→NO2−(aq)+NO3−(aq)+H2O(l)2\mathrm{NO_2(g)} + 2\mathrm{OH^- (aq)} \rightarrow \mathrm{NO_2^- (aq)} + \mathrm{NO_3^- (aq)} + \mathrm{H_2O(l)}2NO2​(g)+2OH−(aq)→NO2−​(aq)+NO3−​(aq)+H2​O(l)

Here nitrogen in NO2\mathrm{NO_2}NO2​ has oxidation state +4+4+4.

In products:

  • In NO2−\mathrm{NO_2^-}NO2−​, N is +3+3+3
  • In NO3−\mathrm{NO_3^-}NO3−​, N is +5+5+5

So the same species undergoes both oxidation and reduction.

  • This is disproportionation.

So, D→IIID \rightarrow IIID→III


  1. Final matching

A−IV,B−I,C−II,D−IIIA-IV, \quad B-I, \quad C-II, \quad D-IIIA−IV,B−I,C−II,D−III

  1. Compare with options

This corresponds to Option A.

  1. Comparison with stored answer

Stored correct answer: A

My derived answer: A

They agree.

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